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Nonlinear Functions

SAT Math· difficulty 4/5

Values: f(0)=100f(0) = 100, f(2)=81f(2) = 81. Assuming exponential decay f(t)=abtf(t) = ab^t, what is bb?

  • A

    0.850.85

  • B

    0.950.95

  • C

    0.90.9

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  • D

    0.810.81

Explanation

ab2=81ab^2 = 81, a=100a = 100, so b2=0.81⇒b=0.9b^2 = 0.81 \Rightarrow b = 0.9.

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