Solve: x+4=x−2\sqrt{x+4} = x - 2x+4=x−2.Ax=0x = 0x=0Bx=−1x = -1x=−1Cx=5x = 5x=5check_circleDx=0x = 0x=0 and x=5x = 5x=5ExplanationSquare: x+4=x2−4x+4⇒x2−5x=0⇒x=0x + 4 = x^2 - 4x + 4 \Rightarrow x^2 - 5x = 0 \Rightarrow x = 0x+4=x2−4x+4⇒x2−5x=0⇒x=0 or x=5x = 5x=5. Check x=0x = 0x=0: 4=2≠−2\sqrt{4} = 2 \neq -24=2=−2, extraneous. Valid x=5x = 5x=5.