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Nonlinear Equations in One Variable and Systems of Equations

SAT Math· difficulty 5/5

Find all real solutions of x4−16=0x^4 - 16 = 0.

  • A

    x=±4x = \pm 4

  • B

    x=±2x = \pm 2

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  • C

    x=2x = 2 only

  • D

    x=±2,±2ix = \pm 2, \pm 2i

Explanation

x4=16x^4 = 16, so x2=4x^2 = 4 (real) or x2=−4x^2 = -4 (no real). Real solutions: x=±2x = \pm 2.

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