Which is equivalent to x3−8x2−4\dfrac{x^3 - 8}{x^2 - 4}x2−4x3−8 for x≠2,−2x \ne 2, -2x=2,−2?Ax2−2x+4x+2\dfrac{x^2 - 2x + 4}{x + 2}x+2x2−2x+4Bx+2x−2\dfrac{x + 2}{x - 2}x−2x+2Cx−2x - 2x−2Dx2+2x+4x+2\dfrac{x^2 + 2x + 4}{x + 2}x+2x2+2x+4check_circleExplanation(x−2)(x2+2x+4)(x−2)(x+2)=x2+2x+4x+2\dfrac{(x-2)(x^2 + 2x + 4)}{(x-2)(x+2)} = \dfrac{x^2 + 2x + 4}{x + 2}(x−2)(x+2)(x−2)(x2+2x+4)=x+2x2+2x+4.