Which expression is equivalent to (x+1)2−(x−1)2(x + 1)^2 - (x - 1)^2(x+1)2−(x−1)2?A2x22x^22x2B000C4x4x4xcheck_circleD2x2x2xExplanationDifference of squares: [(x+1)−(x−1)][(x+1)+(x−1)]=2⋅2x=4x[(x+1) - (x-1)][(x+1)+(x-1)] = 2 \cdot 2x = 4x[(x+1)−(x−1)][(x+1)+(x−1)]=2⋅2x=4x.