Which expression is equivalent to x+3x−2⋅x−2x2−9\dfrac{x + 3}{x - 2} \cdot \dfrac{x - 2}{x^2 - 9}x−2x+3⋅x2−9x−2 for valid xxx?Ax−3x - 3x−3Bx+3x−3\dfrac{x + 3}{x - 3}x−3x+3C1x+3\dfrac{1}{x + 3}x+31D1x−3\dfrac{1}{x - 3}x−31check_circleExplanation(x+3)(x−2)(x−2)(x−3)(x+3)=1x−3\dfrac{(x+3)(x-2)}{(x-2)(x-3)(x+3)} = \dfrac{1}{x - 3}(x−2)(x−3)(x+3)(x+3)(x−2)=x−31.