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Nonlinear Functions

SAT Math· difficulty 4/5

A polynomial f(x)f(x) has zeros x=−3x = -3 (multiplicity 1), x=0x = 0 (multiplicity 2), and x=4x = 4 (multiplicity 1). What is the minimum possible degree of f(x)f(x)?

  • A

    22

  • B

    44

    check_circle
  • C

    33

  • D

    55

Explanation

Sum of multiplicities = 1+2+1=41 + 2 + 1 = 4. Minimum degree is 4.

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