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Equivalent Expressions

SAT Math· difficulty 3/5

Which expression is equivalent to x2−1x+2⋅x+2x+1\dfrac{x^2 - 1}{x + 2} \cdot \dfrac{x + 2}{x + 1} for valid xx?

  • A

    x−1x - 1

    check_circle
  • B

    x+1x + 1

  • C

    x2−1x^2 - 1

  • D

    x−1x+2\dfrac{x-1}{x+2}

Explanation

(x−1)(x+1)x+2⋅x+2x+1=x−1\dfrac{(x-1)(x+1)}{x+2} \cdot \dfrac{x+2}{x+1} = x - 1.

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