If rrr and sss are roots of x2−4x+1=0x^2 - 4x + 1 = 0x2−4x+1=0, find r3+s3r^3 + s^3r3+s3.A525252check_circleB646464C484848D606060Explanationr+s=4r+s = 4r+s=4, rs=1rs = 1rs=1. r3+s3=(r+s)3−3rs(r+s)=64−12=52r^3 + s^3 = (r+s)^3 - 3rs(r+s) = 64 - 12 = 52r3+s3=(r+s)3−3rs(r+s)=64−12=52.