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Nonlinear Functions

SAT Math· difficulty 4/5

The function f(x)=2(x+1)2−5f(x) = 2(x+1)^2 - 5 has minimum value at:

  • A

    (−1,−5)(-1, -5)

    check_circle
  • B

    (1,−5)(1, -5)

  • C

    (1,5)(1, 5)

  • D

    (−1,5)(-1, 5)

Explanation

Vertex at (h,k)=(−1,−5)(h, k) = (-1, -5), which is the minimum point.

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