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Nonlinear Functions

SAT Math· difficulty 5/5

The minimum value of f(x)=x2+bx+5f(x) = x^2 + bx + 5 is 1. What are possible values of bb?

  • A

    b=±6b = \pm 6

  • B

    b=4b = 4 only

  • C

    b=±4b = \pm 4

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  • D

    b=±2b = \pm 2

Explanation

Vertex value =5−b2/4=1= 5 - b^2/4 = 1, so b2=16b^2 = 16, b=±4b = \pm 4.

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