A ball's height is h(t) = -16t^2 + v0 t + 6. The maximum height is 70 ft. What is v0?

64 Max at t = v0/32. Max value = -16(v0/32)^2 + v0(v0/32) + 6 = v0^2/64 + 6 = 70, so v0^2 = 4096, v0 = 64.

Nonlinear Equations in One Variable and Systems of Equations

SAT Math· difficulty 5/5

h(t) = -16t^2 + v_0 t + 6

Explanation

t = v_0/32

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