The minimum of y=3x2+12x+ky = 3x^2 + 12x + ky=3x2+12x+k is 1. What is kkk?A111B131313check_circleC111111D−11-11−11ExplanationVertex x=−12/6=−2x = -12/6 = -2x=−12/6=−2. y(−2)=12−24+k=k−12=1y(-2) = 12 - 24 + k = k - 12 = 1y(−2)=12−24+k=k−12=1, so k=13k = 13k=13.