Solve (x−3)2=16(x-3)^2 = 16(x−3)2=16.Ax=1,−7x = 1, -7x=1,−7Bx=7x = 7x=7 onlyCx=±4x = \pm 4x=±4Dx=−1,7x = -1, 7x=−1,7check_circleExplanationx−3=±4x - 3 = \pm 4x−3=±4, so x=7x = 7x=7 or x=−1x = -1x=−1.