Solve 3x2−2x−1=03x^2 - 2x - 1 = 03x2−2x−1=0.Ax=1,−1/3x = 1, -1/3x=1,−1/3check_circleBx=−1,1/3x = -1, 1/3x=−1,1/3Cx=−1,−1/3x = -1, -1/3x=−1,−1/3Dx=1,1/3x = 1, 1/3x=1,1/3Explanation(3x+1)(x−1)=0(3x + 1)(x - 1) = 0(3x+1)(x−1)=0, so x=1x = 1x=1 or x=−1/3x = -1/3x=−1/3.