If the roots of x2+bx−12=0x^2 + bx - 12 = 0x2+bx−12=0 are rrr and sss with r+s=4r + s = 4r+s=4, what is bbb?A−4-4−4check_circleB444C121212D−12-12−12ExplanationSum of roots =−b= -b=−b, so 4=−b4 = -b4=−b, b=−4b = -4b=−4.