Solve 2x2−8=02x^2 - 8 = 02x2−8=0.Ax=2x = 2x=2 onlyBx=±4x = \pm 4x=±4Cx=4x = 4x=4 onlyDx=±2x = \pm 2x=±2check_circleExplanation2(x2−4)=02(x^2 - 4) = 02(x2−4)=0, so x2=4x^2 = 4x2=4, giving x=±2x = \pm 2x=±2.