Nonlinear Equations in One Variable and Systems of Equations

SAT Math· difficulty 2/5

Solve 2x28=02x^2 - 8 = 0.

  • A

    x=2x = 2 only

  • B

    x=±4x = \pm 4

  • C

    x=4x = 4 only

  • D

    x=±2x = \pm 2

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Explanation

2(x24)=02(x^2 - 4) = 0, so x2=4x^2 = 4, giving x=±2x = \pm 2.

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