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Nonlinear Equations in One Variable and Systems of Equations

SAT Math· difficulty 2/5

Solve x2−9=0x^2 - 9 = 0.

  • A

    x=−3x = -3 only

  • B

    x=±3x = \pm 3

    check_circle
  • C

    x=3x = 3 only

  • D

    x=±9x = \pm 9

Explanation

Difference of squares: (x−3)(x+3)=0(x-3)(x+3) = 0, so x=±3x = \pm 3.

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