NullPointerException is thrown s[0] is null. Calling .length() on null throws a NullPointerException.

ArrayIndexOutOfBoundsException is thrown

Array Creation and Access

AP Computer Science A· difficulty 4/5

String[] s = new String[3];
System.out.println(s[0].length());

What happens?

Explanation

s[0] is null. Calling .length() on null throws a NullPointerException.

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