4 i=0: j=0,1,2,3 (x=4), j=4 breaks outer. x = 4.

Nested Iteration

AP Computer Science A· difficulty 4/5

public static int run() {
    int x = 0;
    outer:
    for (int i = 0; i < 5; i++) {
        for (int j = 0; j < 5; j++) {
            if (i + j == 4) break outer;
            x++;
        }
    }
    return x;
}
// Call: System.out.println(run());

What is printed?

A
$9$
B
$4$
check_circle
C
$16$
D
$5$

Explanation

i=0: j=0,1,2,3 (x=4), j=4 breaks outer. x = 4.

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