<code>a || b && c</code> is equivalent to
- Acheck_circle
a || (b && c) (because && has higher precedence)
- B
Compile error
- C
(a || b) && c
- D
(a && b) || c
Explanation
<code>&&</code> binds tighter than <code>||</code>.
Compound Boolean Expressions
AP Computer Science A· difficulty 4/5
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