If ΔH for 2 X → Y is −80 kJ, ΔH for X → ½Y is
- A
+40 kJ
- Bcheck_circle
−40 kJ
- C
−80 kJ
- D
−160 kJ
Explanation
Halving stoichiometry halves ΔH.
AP Chemistry· difficulty 3/5
If ΔH for 2 X → Y is −80 kJ, ΔH for X → ½Y is
+40 kJ
−40 kJ
−80 kJ
−160 kJ
Explanation
Halving stoichiometry halves ΔH.
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