Burning 0.10 mol of fuel raises 500 g water by 20 °C (c = 4.18 J/g·°C). ΔH (kJ/mol) ≈
- Acheck_circle
−418 kJ/mol
- B
−21 kJ/mol
- C
−4180 kJ/mol
- D
−210 kJ/mol
Explanation
q_water = 500·4.18·20 = 41,800 J = 41.8 kJ. Per 0.10 mol → −418 kJ/mol.
AP Chemistry· difficulty 4/5
Burning 0.10 mol of fuel raises 500 g water by 20 °C (c = 4.18 J/g·°C). ΔH (kJ/mol) ≈
−418 kJ/mol
−21 kJ/mol
−4180 kJ/mol
−210 kJ/mol
Explanation
q_water = 500·4.18·20 = 41,800 J = 41.8 kJ. Per 0.10 mol → −418 kJ/mol.
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