Heating 18 g (1 mol) ice at 0 °C to liquid water at 0 °C requires (ΔH_fus = 6.0 kJ/mol)
- A
1.5 kJ
- B
0.4 kJ
- Ccheck_circle
6.0 kJ
- D
40 kJ
Explanation
All the heat is the fusion enthalpy: 1 mol × 6.0 kJ/mol = 6.0 kJ.
AP Chemistry· difficulty 4/5
Heating 18 g (1 mol) ice at 0 °C to liquid water at 0 °C requires (ΔH_fus = 6.0 kJ/mol)
1.5 kJ
0.4 kJ
6.0 kJ
40 kJ
Explanation
All the heat is the fusion enthalpy: 1 mol × 6.0 kJ/mol = 6.0 kJ.
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