Combustion of 2.00 mol propane (CH): CH + 5 O → 3 CO + 4 HO. Mass of CO produced is
- A
44.0 g
- Bcheck_circle
264 g (2.00 × 3 × 44)
- C
88.0 g
- D
132 g
Explanation
Each mol propane → 3 mol CO. 2.00 mol × 3 × 44.0 g/mol = 264 g.
AP Chemistry· difficulty 4/5
Combustion of 2.00 mol propane (CH): CH + 5 O → 3 CO + 4 HO. Mass of CO produced is
44.0 g
264 g (2.00 × 3 × 44)
88.0 g
132 g
Explanation
Each mol propane → 3 mol CO. 2.00 mol × 3 × 44.0 g/mol = 264 g.
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