Titration of 25.0 mL of HCl with 1.0 M NaOH requires 30.0 mL to reach the equivalence point. The HCl concentration is
- A
0.5 M
- B
1.0 M
- C
0.83 M
- Dcheck_circle
1.2 M
Explanation
M_a V_a = M_b V_b: M_a × 25.0 = 1.0 × 30.0 → M_a = 1.2 M.
Introduction to Titration
AP Chemistry· difficulty 3/5
Want 10 more like this — adaptive to your weak spots?
Related questions
- chem-stim-lab-c29-q2
Why is starch added near the endpoint rather than at the beginning?…
chevron_right - chem-fig-u34-048
The dashed line marks the equivalence point of a strong-acid/strong-base titration. The pH at that point is approximately:…
chevron_right - chem-rxn-067
25.0 mL of 0.100 M H2SO4 requires what volume of 0.200 M NaOH for complete neutralization?…
chevron_right