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AP Chemistry· difficulty 4/5

The freezing point depression of 1.0 m aqueous NaCl (Kf=1.86K_f = 1.86 °C/m) is closest to

  • A

    −1.86-1.86°C

  • B

    −3.72-3.72°C (van't Hoff factor i ≈ 2)

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  • C

    00°C

  • D

    −0.93-0.93°C

Explanation

ΔTf=iKfm=(2)(1.86)(1.0)=3.72\Delta T_f = i K_f m = (2)(1.86)(1.0) = 3.72°C below 0, i.e., −3.72-3.72°C.

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