Ideal Gas Law

AP Chemistry· difficulty 4/5

A gas mixture contains 0.20 mol H2_2, 0.30 mol He, and 0.50 mol N2_2 at total pressure 2.0 atm. The partial pressure of H2_2 is

  • A

    0.20 atm

  • B

    1.0 atm

  • C

    0.40 atm

    check_circle
  • D

    0.10 atm

Explanation

Mole fraction of H2_2 = 0.20/1.00 = 0.20. PH2=(0.20)(2.0)=0.40P_{H_2} = (0.20)(2.0) = 0.40 atm.

Want 10 more like this — adaptive to your weak spots?

Related questions