What pressure does 0.50 mol of an ideal gas exert at 27 °C in a 10.0 L container? (R = 0.0821 L·atm/(mol·K))
- Acheck_circle
1.23 atm
- B
0.62 atm
- C
2.46 atm
- D
12.3 atm
Explanation
T = 300 K. P = nRT/V = (0.50)(0.0821)(300)/10.0 = 12.32/10 = 1.23 atm.
Ideal Gas Law
AP Chemistry· difficulty 3/5
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