AP Chemistry· difficulty 4/5
Three trials of A + B → C give: (1) [A]=0.10, [B]=0.10, rate=2.0e-3; (2) [A]=0.20, [B]=0.10, rate=8.0e-3; (3) [A]=0.20, [B]=0.20, rate=1.6e-2. Order in A is
1
0
2 (rate quadruples when [A] doubles, B fixed)
3
Explanation
From trial 1→2 ([A] 2x, [B] fixed), rate goes 2.0e-3 → 8.0e-3 = 4x = 2. Order in A = 2.
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