For a second-order reaction with k=0.05 M⁻¹·s⁻¹ and [A]₀=0.40 M, t₁/₂ is
- A
5 s
- B
100 s
- Ccheck_circle
50 s
- D
10 s
Explanation
t₁/₂ = 1/(k[A]₀) = 1/(0.05·0.40) = 50 s.
AP Chemistry· difficulty 3/5
For a second-order reaction with k=0.05 M⁻¹·s⁻¹ and [A]₀=0.40 M, t₁/₂ is
5 s
100 s
50 s
10 s
Explanation
t₁/₂ = 1/(k[A]₀) = 1/(0.05·0.40) = 50 s.
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