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Properties of the Equilibrium Constant

AP Chemistry· difficulty 4/5

At 500 K, KpK_p = 1.5 for N2O4(g)⇌2NO2(g)N_2O_4(g) \rightleftharpoons 2NO_2(g). What is KcK_c? (R = 0.08206 L·atm/mol·K)

  • A

    Kc=0.244K_c = 0.244

  • B

    Kc=0.0366K_c = 0.0366

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  • C

    Kc=1.50K_c = 1.50

  • D

    Kc=61.5K_c = 61.5

Explanation

Kp=Kc(RT)ΔnK_p = K_c(RT)^{\Delta n} with Δn\Delta n = 2-1 = 1. KcK_c = Kp/(RT)K_p/(RT) = 1.5/((0.08206)(500)) = 1.5/41.03 = 0.0366.

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