Gibbs Free Energy and Thermodynamic Favorability

AP Chemistry· difficulty 4/5

For CaCO₃(s) → CaO(s) + CO₂(g): ΔH° = +178 kJ; ΔS° = +161 J/K.

+ΔG -ΔG T (K)

Approximately at what temperature does the decomposition become spontaneous?

  • A

    ≈ 1106 K

    check_circle
  • B

    ≈ 1780 K

  • C

    ≈ 298 K

  • D

    ≈ 161 K

Explanation

T = ΔH/ΔS = 178000 J / 161 J·K⁻¹ ≈ 1106 K (above this T, ΔG < 0).

Want 10 more like this — adaptive to your weak spots?

Related questions