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Heat Capacity and Calorimetry

AP Chemistry· difficulty 3/5

Coffee-cup calorimetry: 100. g water; ΔT = +6.5°C; c = 4.18 J/(g·°C).

100. g H₂O T₁ = 22.0°C T₂ = 28.5°C

What is q absorbed by the water?

  • A

    -2.7 kJ

  • B

    +650 J

  • C

    +2.7 kJ

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  • D

    +27 kJ

Explanation

q = m·c·ΔT = (100.)(4.18)(6.5) ≈ 2720 J ≈ +2.7 kJ; positive because water warms.

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