18.0 g H₂O at 0°C is heated to liquid at 0°C. ΔHfus = 6.01 kJ/mol.
How much heat is required for the melting step alone?
- Acheck_circle
6.01 kJ
- B
108 kJ
- C
0.601 kJ
- D
60.1 kJ
Explanation
18.0 g / 18.0 g·mol⁻¹ = 1.00 mol; q = (1.00)(6.01 kJ/mol) = 6.01 kJ.