For a second-order reaction, t1/2 = 1/(k[A]0).
As [A]0 decreases over time, successive half-lives:
- A
Become constant only after 3 half-lives
- B
Get shorter
- Ccheck_circle
Get longer
- D
Stay the same
Explanation
Since t1/2 ∝ 1/[A]0, lower starting concentration means longer half-life. Successive halvings take longer.