Using Hess's law, ΔH for A → C is
- A
+80 kJ
- B
−140 kJ
- C
+140 kJ
- Dcheck_circle
−80 kJ
Explanation
ΔH(A → B) + ΔH(B → C) = +30 − 110 = −80 kJ.
Energy Diagrams
AP Chemistry· difficulty 3/5
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AP Chemistry· difficulty 3/5
Using Hess's law, ΔH for A → C is
+80 kJ
−140 kJ
+140 kJ
−80 kJ
Explanation
ΔH(A → B) + ΔH(B → C) = +30 − 110 = −80 kJ.
Want 10 more like this — adaptive to your weak spots?