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Common-Ion Effect

AP Chemistry· difficulty 4/5

The solubility of PbCl2_2 (Ksp=1.6×10−5K_{sp} = 1.6 \times 10^{-5}) in 0.10 M NaCl is approximately

  • A

    Same as in pure water

  • B

    Zero

  • C

    1.6×10−31.6 \times 10^{-3} M (lower because of common-ion effect)

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  • D

    Higher than in pure water

Explanation

With [Cl−^-] = 0.10 M, Ksp=s(0.10)2=0.01sK_{sp} = s(0.10)^2 = 0.01s. s=1.6×10−5/0.01=1.6×10−3s = 1.6\times10^{-5}/0.01 = 1.6\times10^{-3} M (much lower than 1.6×10−21.6\times10^{-2} in pure water).

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