K_sp(AgCl) = 1.6×10⁻¹⁰. Molar solubility (M) is
- A
4×10⁻⁵
- Bcheck_circle
1.3×10⁻⁵
- C
5×10⁻¹⁰
- D
1.6×10⁻¹⁰
Explanation
s² = 1.6×10⁻¹⁰ → s ≈ 1.3×10⁻⁵ M.
Introduction to Solubility Equilibria
AP Chemistry· difficulty 4/5
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