Mass of Ag deposited (M = 108) by 0.020 mol Ag is
- A
1.08 g
- B
108 g
- C
10.8 g
- Dcheck_circle
2.16 g
Explanation
0.020 × 108 = 2.16 g.
AP Chemistry· difficulty 4/5
Mass of Ag deposited (M = 108) by 0.020 mol Ag is
1.08 g
108 g
10.8 g
2.16 g
Explanation
0.020 × 108 = 2.16 g.
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