Coulombs to deposit 1 mol Cu (Cu²⁺ + 2 e⁻ → Cu) is

192,970 C n = 2 mol e⁻ → 2 × 96,485 = 192,970 C per mol Cu deposited.

Electrolysis and Faraday's Law

AP Chemistry· difficulty 4/5

Coulombs to deposit 1 mol Cu (Cu²⁺ + 2 e⁻ \to Cu) is

Explanation

n = 2 mol e⁻ \to 2 \times 96,485 = 192,970 C per mol Cu deposited.

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