Balanced half-reaction: Cr₂O₇²⁻ → 2 Cr³⁺ in acidic solution requires (besides electrons)

7 H₂O on right, 14 H⁺ on left 14 H⁺ + 6 e⁻ + Cr₂O₇²⁻ → 2 Cr³⁺ + 7 H₂O.

7 H₂O on left, 14 H⁺ on right

7 H₂O on right, 14 H⁺ on left

Oxidation-Reduction Reactions

AP Chemistry· difficulty 3/5

Balanced half-reaction: Cr₂O₇²⁻ \to 2 Cr³⁺ in acidic solution requires (besides electrons)

Explanation

14 H⁺ + 6 e⁻ + Cr₂O₇²⁻ \to 2 Cr³⁺ + 7 H₂O.

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