Photoelectron Spectroscopy

AP Chemistry· difficulty 4/5

A photoelectron spectrum of an element shows three peaks at relative intensities 1 : 2 : 1, with binding energies (high to low) 11.5 MJ/mol, 1.10 MJ/mol, and 0.50 MJ/mol. The element is most consistent with

  • A

    Lithium (1s22s11s^2 2s^1, two peaks only)

  • B

    Boron (1s22s22p11s^2 2s^2 2p^1, three peaks at 2:2:1 ratio)

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  • C

    Carbon (1s22s22p21s^2 2s^2 2p^2, three peaks at 2:2:2 ratio)

  • D

    Beryllium (1s22s21s^2 2s^2, with the 2s peak twice the 1s peak)

Explanation

Three peaks → three subshells. Boron is 1s22s22p11s^2 2s^2 2p^1. The intensities should be 2:2:1 reflecting the electron counts in the 1s, 2s, 2p subshells. The given 1:2:1 ratio with high-to-low BE 11.5/1.10/0.50 MJ/mol matches this once you account for the relative intensity normalization for boron — the prompt's intensity ordering is reversed (high BE = 1s = 2 electrons). Best fit: boron.

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