Acid-Base Titrations

AP Chemistry· difficulty 4/5

During a weak acid-strong base titration, at the HALF-equivalence point

  • A

    All acid is neutralized

  • B

    pH = pKapK_a ([HA] = [A^-], so log=0\log = 0)

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  • C

    pH = 7

  • D

    pH = pKb_b

Explanation

At half-equivalence, half the acid has been converted to A^-. pH = pKa_a + log(1) = pKa_a.

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