During a weak acid-strong base titration, at the HALF-equivalence point
- A
All acid is neutralized
- Bcheck_circle
pH = ([HA] = [A], so )
- C
pH = 7
- D
pH = pK
Explanation
At half-equivalence, half the acid has been converted to A. pH = pK + log(1) = pK.
AP Chemistry· difficulty 4/5
During a weak acid-strong base titration, at the HALF-equivalence point
All acid is neutralized
pH = ([HA] = [A], so )
pH = 7
pH = pK
Explanation
At half-equivalence, half the acid has been converted to A. pH = pK + log(1) = pK.
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