For f(x)=x3f(x) = x^3f(x)=x3, evaluate limh→0(2+h)3−8h\displaystyle\lim_{h\to 0} \dfrac{(2+h)^3 - 8}{h}h→0limh(2+h)3−8.A121212check_circleB444C888D000ExplanationExpand or recognize: this is f′(2)f'(2)f′(2) for f(x)=x3f(x) = x^3f(x)=x3, i.e. 3⋅22=123 \cdot 2^2 = 123⋅22=12.