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Determining Limits Using Algebraic Properties

AP Calculus AB· difficulty 1/5

Evaluate lim⁡x→π/2sin⁡x\displaystyle\lim_{x\to\pi/2} \sin x.

  • A

    22\tfrac{\sqrt 2}{2}

  • B

    11

    check_circle
  • C

    12\tfrac{1}{2}

  • D

    00

Explanation

sin⁡\sin is continuous everywhere; sin⁡(π/2)=1\sin(\pi/2) = 1.

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