Asymptotes and Limits at Infinity

AP Calculus AB· difficulty 3/5

\displaystyle\lim_{x\to\infty}\dfrac{\sqrt{4x^2 + 1}}{2x + 3}

A
$0$
B
$1$
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C
$2$
D
$\tfrac{1}{2}$

Explanation

x > 0

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