Evaluate limx→2+1x−2\displaystyle\lim_{x \to 2^+}\dfrac{1}{x - 2}x→2+limx−21.A−∞-\infty−∞B111C+∞+\infty+∞check_circleD000ExplanationAs x→2+x \to 2^+x→2+, x−2→0+x - 2 \to 0^+x−2→0+, so 1/(x−2)→+∞1/(x-2) \to +\infty1/(x−2)→+∞.