Given ∫abf=7\int_a^b f = 7∫abf=7 and ∫abg=−3\int_a^b g = -3∫abg=−3, ∫ab(f−2g)=\int_a^b (f - 2g) =∫ab(f−2g)=A101010B−1-1−1C131313check_circleD111Explanation7−2(−3)=7+6=137 - 2(-3) = 7 + 6 = 137−2(−3)=7+6=13.