Integration by Substitution

AP Calculus AB· difficulty 2/5

e2xdx=\displaystyle\int e^{2x}\,dx =

  • A

    2e2x+C2 e^{2x} + C

  • B

    e2x2+C\dfrac{e^{2x}}{2} + C

    check_circle
  • C

    ex2+C\dfrac{e^x}{2} + C

  • D

    e2x+Ce^{2x} + C

Explanation

u=2xu = 2x. eudu/2=eu/2\int e^u\,du/2 = e^u/2.

Want 10 more like this — adaptive to your weak spots?

Related questions